3^y*9^x=81 log(x+y)^2-log(x)=2*log(3)

$$3^{y} 9^{x} = 81$$

2
log (x + y) – log(x) = 2*log(3)

$$- log{left (x right )} + log^{2}{left (x + y right )} = 2 log{left (3 right )}$$

x1 = 0.5244806819014791 – 1.435425536851978e-31*i
y1 = 2.951038636197042 + 2.870851016651155e-31*i

x2 = 0.5244806819014791 – 4.132871836627936e-25*i
y2 = 2.951038636197042 + 8.265743673352732e-25*i

x3 = 0.5244806819014791
y3 = 2.951038636197042